How best to use ViewerFilter on a TreeViewer?

2020-08-25 05:43发布

I am applying a ViewerFilter to a tree of a few branches, but mostly leaves. The filter really applies to the leaves, using properties within the leaf. All branches are left untouched so that their leaves can appear.

However I would like to filter out branches that contain no selected leaves, and I can see no mechanism within ViewerFilter that allows this.

Is this possible at all?

For example, given the notional tree below (where b is a branch, a L is a leaf)

b0
  b1
    L2
    L4
    L8
  b2
    L1
    L3
    L5

I would like to apply a ViewerFilter that only selects even leaves and branches that contain even leaves. The resulting tree would be ..

b0
  b1
    L2
    L4
    L8

.. where branch b2 does not display as it contains no selected children, but branches b0 and b1 do.

4条回答
迷人小祖宗
2楼-- · 2020-08-25 06:08

Also have a look at org.eclipse.ui.dialogs.FilteredTree which the right thing in regard to child leaves.

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神经病院院长
3楼-- · 2020-08-25 06:16
class MyFilter extends ViewerFilter{

  private boolean isLeaf(Object element){
    // implement this
  }

  private boolean isEvenLeaf(Object leaf){
    // implement this
  }

  @Override
  public boolean select(Viewer viewer, Object parentElement, Object element){
    if (isLeaf(element))
      return isEventLeaf(element);
    else {
      StructuredViewer sviewer = (StructuredViewer) viewer;
      ITreeContentProvider provider = (ITreeContentProvider) sviewer.getContentProvider();
      for (Object child: provider.getChildren(element)){
        if (select(viewer, element, child))
          return true;
      }
      return false;
    }
  }
}
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虎瘦雄心在
4楼-- · 2020-08-25 06:17

I'm not sure what you mean by selected leaves. If you mean selected in the view, you can find this out by calling Viewer.getSelection(). The select method that you implement in your filter passes in the viewer, parent, and leaf. You should be able to use this information to decide if the leaf is selected or not and filter them out. If you can give some more information, I can probably answer with more detail.

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劳资没心,怎么记你
5楼-- · 2020-08-25 06:21

Yes, if you don't filter out the branch nodes, they'll be shown even if there are no leaves in it. If you want the filter to be permanently on, something you can consider is using the ITreeContentProvider as a filter.

Since the content provider has both getChildren() and hasChildren() methods, you have a little more control.

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