我怎么知道在两者之间的分钟差datetime
对象?
Answer 1:
>>> import datetime
>>> a = datetime.datetime.now()
>>> b = datetime.datetime.now()
>>> c = b - a
datetime.timedelta(0, 8, 562000)
>>> divmod(c.days * 86400 + c.seconds, 60)
(0, 8) # 0 minutes, 8 seconds
Answer 2:
在新的Python 2.7是timedelta
实例方法.total_seconds()
从Python文档,这相当于(td.microseconds + (td.seconds + td.days * 24 * 3600) * 10**6) / 10**6
。
参考: http://docs.python.org/2/library/datetime.html#datetime.timedelta.total_seconds
>>> import datetime
>>> time1 = datetime.datetime.now()
>>> time2 = datetime.datetime.now() # waited a few minutes before pressing enter
>>> elapsedTime = time2 - time1
>>> elapsedTime
datetime.timedelta(0, 125, 749430)
>>> divmod(elapsedTime.total_seconds(), 60)
(2.0, 5.749430000000004) # divmod returns quotient and remainder
# 2 minutes, 5.74943 seconds
Answer 3:
只需减去从另一个。 你得到一个timedelta
与区别对象。
>>> import datetime
>>> d1 = datetime.datetime.now()
>>> d2 = datetime.datetime.now() # after a 5-second or so pause
>>> d2 - d1
datetime.timedelta(0, 5, 203000)
你可以转换dd.days
, dd.seconds
和dd.microseconds
到几分钟。
Answer 4:
使用日期时间例子
>>> from datetime import datetime
>>> then = datetime(2012, 3, 5, 23, 8, 15) # Random date in the past
>>> now = datetime.now() # Now
>>> duration = now - then # For build-in functions
>>> duration_in_s = duration.total_seconds() # Total number of seconds between dates
持续时间在年
>>> years = divmod(duration_in_s, 31556926)[0] # Seconds in a year=31556926.
时间以天为单位
>>> days = duration.days # Build-in datetime function
>>> days = divmod(duration_in_s, 86400)[0] # Seconds in a day = 86400
时间以小时为单位
>>> hours = divmod(duration_in_s, 3600)[0] # Seconds in an hour = 3600
时间以分钟为单位
>>> minutes = divmod(duration_in_s, 60)[0] # Seconds in a minute = 60
持续时间(秒)
>>> seconds = duration.seconds # Build-in datetime function
>>> seconds = duration_in_s
持续时间在微秒
>>> microseconds = duration.microseconds # Build-in datetime function
这两个日期之间的总时间
>>> days = divmod(duration_in_s, 86400) # Get days (without [0]!)
>>> hours = divmod(days[1], 3600) # Use remainder of days to calc hours
>>> minutes = divmod(hours[1], 60) # Use remainder of hours to calc minutes
>>> seconds = divmod(minutes[1], 1) # Use remainder of minutes to calc seconds
>>> print("Time between dates: %d days, %d hours, %d minutes and %d seconds" % (days[0], hours[0], minutes[0], seconds[0]))
或者干脆:
>>> print(now - then)
Answer 5:
如果a
, b
是datetime对象,然后找到在Python 3它们之间的时间差:
from datetime import timedelta
time_difference = a - b
time_difference_in_minutes = time_difference / timedelta(minutes=1)
在早期的Python版本:
time_difference_in_minutes = time_difference.total_seconds() / 60
如果a
, b
是如返回天真datetime对象datetime.now()
那么如果对象表示本地时间与UTC不同抵消例如,围绕DST转换或过去/将来的日期,结果可能是错误的。 更多细节: 查找,如果24个小时有日期时间之间传递- Python的 。
为了得到可靠的结果,使用UTC时间或时区感知datetime对象。
Answer 6:
使用divmod:
now = int(time.time()) # epoch seconds
then = now - 90000 # some time in the past
d = divmod(now-then,86400) # days
h = divmod(d[1],3600) # hours
m = divmod(h[1],60) # minutes
s = m[1] # seconds
print '%d days, %d hours, %d minutes, %d seconds' % (d[0],h[0],m[0],s)
Answer 7:
这是我得到的两个datetime.datetime对象之间经过的小时数:
before = datetime.datetime.now()
after = datetime.datetime.now()
hours = math.floor(((after - before).seconds) / 3600)
Answer 8:
如果仅想了解的天数:timedelta有一个“天”属性。 你可以简单地查询该。
>>>from datetime import datetime, timedelta
>>>d1 = datetime(2015, 9, 12, 13, 9, 45)
>>>d2 = datetime(2015, 8, 29, 21, 10, 12)
>>>d3 = d1- d2
>>>print d3
13 days, 15:59:33
>>>print d3.days
13
Answer 9:
只是认为它可能是提到的格式,以及在问候timedelta有用。 strptime()分析表示根据格式的时间的字符串。
from datetime import datetime
datetimeFormat = '%Y/%m/%d %H:%M:%S.%f'
time1 = '2016/03/16 10:01:28.585'
time2 = '2016/03/16 09:56:28.067'
time_dif = datetime.strptime(time1, datetimeFormat) - datetime.strptime(time2,datetimeFormat)
print(time_dif)
这将输出:0:05:00.518000
Answer 10:
我用somethign这样的:
from datetime import datetime
def check_time_difference(t1: datetime, t2: datetime):
t1_date = datetime(
t1.year,
t1.month,
t1.day,
t1.hour,
t1.minute,
t1.second)
t2_date = datetime(
t2.year,
t2.month,
t2.day,
t2.hour,
t2.minute,
t2.second)
t_elapsed = t1_date - t2_date
return t_elapsed
# usage
f = "%Y-%m-%d %H:%M:%S+01:00"
t1 = datetime.strptime("2018-03-07 22:56:57+01:00", f)
t2 = datetime.strptime("2018-03-07 22:48:05+01:00", f)
elapsed_time = check_time_difference(t1, t2)
print(elapsed_time)
#return : 0:08:52
Answer 11:
这是找到当前时间和上午9:30之间的区别
t=datetime.now()-datetime.now().replace(hour=9,minute=30)
Answer 12:
这是用我的方法mktime 。
from datetime import datetime, timedelta
from time import mktime
yesterday = datetime.now() - timedelta(days=1)
today = datetime.now()
difference_in_seconds = abs(mktime(yesterday.timetuple()) - mktime(today.timetuple()))
difference_in_minutes = difference_in_seconds / 60
Answer 13:
以其他方式获取日期之间的差异;
import dateutil.parser
import datetime
last_sent_date = "" # date string
timeDifference = current_date - dateutil.parser.parse(last_sent_date)
time_difference_in_minutes = (int(timeDifference.days) * 24 * 60) + int((timeDifference.seconds) / 60)
因此,获得输出最小。
谢谢