## How do I remove axis from a rotation matrix?

2020-08-20 04:46发布

# 问题:

I have an opengl arbitrary rotation matrix and would like to remove the X & Y axis, leaving me with only the Z axis?

Is this possible? Any pointers on how to do it?

# 回答1:

Just thinking out loud here, but can't you use the matrix to rotate a vector like (1,0,0), then do atan2(y,x) to see how much it's rotated and then build a new matrix to rotate through the Z axis by that much?

# 回答2:

In a rotation that is only around the z-axis, the z axis should remain unchanged. So the above recommendation is sort of the reverse of what you want.

Let's assume you have an arbitrary OpenGL matrix:

``````    | r_xx r_xy r_xz t_x |
| r_yx r_yy r_yz t_y |
M = | r_zx r_zy r_zz t_z |
|  0    0    0    1  |
``````

Where the t_i elements are translations and the r_jk elements are components of rotation. You want a matrix that looks like this:

``````| cos(th) sin(th)  0  t_x |
|-sin(th) cos(th)  0  t_y |
|  0       0       1  t_z |
|  0       0       0   1  |
``````

Unless the matrix has scaling factors or is close to a singularity, you should be able to get this by just zeroing out the z parts of the matrix and then re-normalizing the columns. Since an OpenGL matrix is column major order:

``````double xLen = sqrt(M[0]*M[0] + M[1]*M[1]); // Singularity if either of these
double yLen = sqrt(M[4]*M[4] + M[5]*M[5]); //  is equal to zero.

M[0]/=xLen; M[1]/=xLen; M[2]=0; // Set the x column
M[4]/=yLen; M[5]/=yLen; M[6]=0; // Set the y column
M[8]=0; M[9]=0; M[10]=1;        // Set the z column
//Don't change the translation column
``````

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