How to check if a div is visible state or not?

问题:

I have tabs like this.

<li id="singlechatpanel-1" style="visibility: hidden;">
     //content
</li>

Trying to check it like this:

$(".subpanel a").click(function() 
     {
        var chatterNickname = $(this).text();

        if(!$("#singlechatpanel-1").is(':visible'))
        {
            alert("Room 1 is filled.");
            $("#singlechatpanel-1").css({'visibility':'visible'});
            $("#singlechatpanel-1 #chatter_nickname").html("Chatting with: " + chatterNickname);
        }

If condition always returns false. How can I check visibility state of this div?

回答1:

is(':visible') checks the display property of an element, you can use css method.

if (!$("#singlechatpanel-1").css('visibility') === 'hidden') {
   // ...
}

If you set the display property of the element to none then your if statement returns true.

回答2:

Check if it's visible.

$("#singlechatpanel-1").is(':visible');

Check if it's hidden.

$("#singlechatpanel-1").is(':hidden');

回答3:

if element is hide by jquery then use

if($("#elmentid").is(':hidden'))

回答4:

You can use .css() to get the value of "visibility":

 if( ! ( $("#singlechatpanel-1").css('visibility') === "hidden")){
 }

http://api.jquery.com/css/

回答5:

You can use (':hidden') method to find if your div is visible or not.. Also its a good practice to cache a element if you are using it multiple times in your code..

$(".subpanel a").click(function() 
     {
        var chatterNickname = $(this).text();
        var $chatPanel = $("#singlechatpanel-1");

        if(!$chatPanel.is(':hidden'))
        {
            alert("Room 1 is filled.");
            $chatPanel.show();
            $("#singlechatpanel-1 #chatter_nickname").html("Chatting with: " + chatterNickname);
        }
});

回答6:

if (!$('#singlechatpanel-1').css('display') == 'none') {
   alert('visible');
}else{
   alert('hidden');
}

回答7:

Add your li to a class, and do $(".myclass").hide(); at the start to hide it instead of the visibility style attribute.

As far as I know, jquery uses the display style attribute to show/hide elements instead of visibility (may be wrong on that one, in either case the above is worth trying)